235k views
4 votes
Find an equation for the line that passes through the points (-6, -6) and (4,2).

2 Answers

6 votes
use the slope formula y2-y1/x2-x1

2-(-6)/4-(-6) = 4/5

Then,

Solve for b by using one of the points to substitute x and y.

y = mx + b --> 2 = 4/5(4) + b

2 = 4/5(4) + b

The equation for the line that passes through both points is:

y = 4/5x - 1.2
User Halfred
by
7.9k points
2 votes

Answer:

y-(-6)=8/10(x-(-6)

Explanation:

Using slope point formula (y-y1=m(x-x1)) we can sue the given coordinates to fill in the equation.

y1=-6 x1=-6

Substitute into the equation: y-(-6)=m(x-(-6))

Next we have to find slope using slope formula (y2-y1/x2-x1) 2-(-6)/4-(-6)=8/10

Substitute in for m: y-(-6)=8/10(x-(-6))

You now have the completed equation!

-Hope this helped

User Shibi
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories