Question

what is the equation for a line that passes through the point (8,-1) and is parallel to the line that passes through points (-2,2) and (6,6)

Answer 1

Answer:y=2x-15

Explanation:

First, we find the slope of the first line
Slope equation:

`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

Plug-in values

`(6-2)/(6-(-2))`

=
`(4)/(8)`=
`(1)/(2)`

Slope=1/2

Remember that parallel lines have the same slope.

Now, we use the slope to get the y-intercept.

We start from (8,-1)

We go up 1 (rise) and right 2 (run), or the opposite of the slope (-1 rise, -2 run).

We get a y-intercept of -5.

Plug into y=mx+b

y=1/2x-5