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In the triangle below, angle BCA is obtuse.
Calculate angle BCA to 1 d.p

In the triangle below, angle BCA is obtuse. Calculate angle BCA to 1 d.p-example-1
User Jeff Hall
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2 Answers

1 vote

Answer:

56.27⁰

Explanation:

a/sinA =b/sinB

35/sin 50⁰ = 38/sin B

cross multiply

35sinB = 38sin50⁰

sin B=29.1096/35

sinB=0.8317 find the inverse sine

angle BCA= 56.27⁰

User Andyz Smith
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4 votes

Perpendicular lines intersect to form four right angles.: ∠BCA = 90°

For example, let's say a=5, b=7, and c=8 (these are just example values). You would substitute these into the equation:

c - accros ⁵²- ⁷²- ⁸²/2-5-7)

To calculate ∠BCA in a triangle where ∠BCA is obtuse, you can use the Law of Cosines. The Law of Cosines states:

ᶜ²-ᵃ²+ᵇ²-2abcos(c)

where a ,b and c, are the side lengths of the triangle opposite to angles, A,B, C respectively. In this case, we are interested in ∠C , which is ∠BCA.

Identify the side lengths:

Let a be the side length opposite to ∠A.

Let b be the side length opposite to ∠B

Let c be the side length opposite to ∠C. (BCA)

Write down the Law of Cosines equation:

ᶜ²- ᵃ² + ᵇ² - 2abcos (c)

Substitute the known values into the equation:

a and b are the side lengths opposite to angles A and B, respectively.

c is the side length opposite to angle C (BCA).

C is the ∠BCA that we want to find.

Solve for C:

cos (C) -( ᵃ²+ᵇ²+ᶜ²/2ab)

Substitute the values of a, b, and c into the equation and calculate the result.

For example, let's say a=5, b=7, and c=8 (these are just example values). You would substitute these into the equation:

c - accros ⁵²- ⁷²- ⁸²/2-5-7)

Calculate the expression to find the measure of ∠BCA.

User James Simm
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