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What are the x intercepts of the function f(x)= 5x^2-25x over x​

User BenceL
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2 Answers

20 votes
20 votes

Final answer:

The x-intercepts of the function f(x) = 5x^2 - 25x / x are x = 0 and x = 5.

Step-by-step explanation:

The x-intercepts of a function are the values of x where the graph of the function intersects the x-axis.

To find the x-intercepts of the function f(x) = 5x^2 - 25x / x, we set f(x) equal to zero and solve for x.

5x^2 - 25x / x = 0

Since division by zero is undefined, we need to eliminate the denominator.

We can do this by multiplying both sides of the equation by x:

5x^2 - 25x = 0

Now, we can factor out the common factor of x and solve for x:

x(5x - 25) = 0

Setting each factor equal to zero gives us:

x = 0

and

5x - 25 = 0

From the second equation, we can solve for x:

5x = 25

x = 5

Therefore, the x-intercepts of the function f(x) = 5x^2 - 25x / x are x = 0 and x = 5.

User Hgolov
by
2.7k points
18 votes
18 votes

Answer :X = 0 OR X = 5

Step-by-step explanation:

User SeedyROM
by
2.7k points