Answer:
Let A B = x miles = 18
B C = y miles
t1 = (18 + y) / 10 time for biker 1 to reach C
t2 = y / 4 = y / 4
t1 = t2 both bikers reach C at same time
(18 + y) / 10 = y / 4
72 + 4 y = 10 y
y = 12 distance from B to C
Check:
A C = 12 + 18 = 30 km
t1 = (18 + 12) / 10 = 3 hr
t2 = 12 / 4 = 3 hrs
So both meet at C in 3 hrs