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Finding the charge: Two spheres 6.0 units apart, attract each other with a force of 3 x 10 9 N. Determine them magnitude of the charge on one sphere if the other sphere has a charge of 9 E-8.

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The force of attraction between two charged spheres is given by Coulomb's law:

F = k * q1 * q2 / r^2

where F is the force of attraction, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges on the spheres, and r is the distance between the centers of the spheres.

Given that the force of attraction between the two spheres is 3 x 10^9 N and the distance between them is 6.0 units, we can substitute the values into Coulomb's law to find the magnitude of the charge on one of the spheres:

3 x 10^9 = k * q1 * 9 x 10^-8 / 6^2

Solving for q1, we get:

q1 = (3 x 10^9 * 6^2) / (k * 9 x 10^-8)

q1 = (3 x 10^9 * 36) / (8.99 x 10^9 * 9 x 10^-8)

q1 = 2.16 x 10^-7 C

So, the magnitude of the charge on one of the spheres is 2.16 x 10^-7 C
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