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The radius of a wheel is 0.900 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel spin CCW about its central axis. Ignore the mass of the rope.

What is the angular displacement Δθ, in radians, of the wheel during 1.20 revolution?

1 Answer

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Answer:

θ = 2 π N angle subtended in N revolutions (2 π rad / Rev)

θ = 2 π * 1.2 = 2.4 π angle subtended in 1.2 rev

User Guy Mograbi
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