Question

What mass of solid FeCl3 is formed when 200 mL of 0.375 N Fe3+ is mixed with 400 mL of 0.175 N Cl2?

Please anwer

Answer 1

4.05 g

Step-by-step explanation:

The balanced chemical equation for the reaction between Fe3+ and Cl2 is:

Fe3+ + 3 Cl2 -> FeCl3

To find the amount of FeCl3 formed, we need to find the limiting reactant and then calculate the amount of product that can be formed.

First, we calculate the number of moles of Fe3+ and Cl2:

Fe3+: 0.375 N * 200 mL = 0.075 mol

Cl2: 0.175 N * 400 mL = 0.07 mol

Since Fe3+ is the limiting reactant, we can use its moles to determine the amount of FeCl3 that can be formed:

0.075 mol Fe3+ * (1 mol FeCl3 / 3 mol Cl2) = 0.025 mol FeCl3

Finally, to find the mass of FeCl3, we use its molar mass:

0.025 mol FeCl3 * 162.2 g/mol = 4.05 g FeCl3.

So, 4.05 g of FeCl3 is formed when 200 mL of 0.375 N Fe3+ is mixed with 400 mL of 0.175 N Cl2.