Approximately
60
g of
C
6
H
12
O
6
.
Step-by-step explanation:
We have the balanced equation (without state symbols):
6
H
2
O
+
6
C
O
2
→
C
6
H
12
O
6
+
6
O
2
So, we would need six moles of carbon dioxide to fully produce one mole of glucose.
Here, we got
88
g
of carbon dioxide, and we need to convert it into moles.
Carbon dioxide has a molar mass of
44
g/mol
. So here, there exist
88
g
44
g
/mol
=
2
mol
Since there are two moles of
C
O
2
, we can produce
2
6
⋅
1
=
1
3
moles of glucose
(
C
6
H
12
O
6
)
.
We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.
Glucose has a molar mass of
180.156
g/mol
. So here, the mass of glucose produced is
1
3
mol
⋅
180.156
g
mol
≈
60
g
to the nearest whole number.
So, approximately
60
grams of glucose will be produced