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Please help me with #8 and 9

NO LINKS!! Please help me with #8 and 9-example-1
User Perror
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1 Answer

4 votes

Answer:

8. TN = 22 units

9. RT = √(165) units

Explanation:

It appears that point T is the circumcenter of triangle MNP.

A circumcenter of a triangle is:

  • The center of a circle that passes through each vertex of a triangle.
  • The point at which the perpendicular bisectors of the sides of the triangle intersect.

As a perpendicular bisector is a line that divides another line segment into two equal parts at a right angle, then:

  • MR = RN
  • NS = SP
  • PQ = QM

As point T is the circumcenter, ΔMTN, ΔNTP and ΔMTP are isosceles triangles and MT, TP and TN are the radius of the circumcircle.

Therefore:

  • MT = TP = TN

Question 8

To find the length of TN, find the value of x by equating the given expressions for MP and TP:


\implies \sf MT = TP


\implies 6x - 56 = 3x - 17


\implies 3x = 39


\implies x = 13

Substitute the found value of x into the expression for TP:


\implies \textsf{TP} = 3(13) - 17


\implies \textsf{TP} = 22

Therefore, as TN = TP then TN = 22 units.

Question 9

First find the value of x by equating the given expressions for TN and TP:


\implies \sf TN=TP


\implies 4x-17=x+10


\implies 3x=27


\implies x=9

Substitute the found value of x into the expression for TN:


\implies \textsf{TN} = 4(9) - 17


\implies \textsf{TN} = 19

As RT is the perpendicular bisector of MN, then ΔTRN is a right triangle where ∠TRN is 90°.

Given:

  • RN = 14
  • TN = 19

To calculate the length of RT, use Pythagoras Theorem:


\implies \sf RN^2+RT^2=TN^2


\implies \sf RT=√(TN^2-RN^2)


\implies \sf RT=√(19^2-14^2)


\implies \sf RT=√(165)

User Changeling
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