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Please help me with #18, 19, & 20

NO LINKS!! Please help me with #18, 19, & 20-example-1
User Omtara
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1 Answer

2 votes

Answer:

  • 18) 30°,
  • 19) 38,
  • 20) 41.34.

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Since P is incenter, we have properties of incenter applicable to given questions:

  • P is the intersection of angle bisectors;
  • P is equidistant from the sides of the triangle.

Question 18

Since JN is angle bisector of ∠J, set up equation:

  • 7x - 6 = 5x + 4
  • 7x - 5x = 4 + 6
  • 2x = 10
  • x = 6

Angle measures of the triangle are:

  • m∠J = 2 (5*6 + 4) = 3(34) = 68
  • m∠L = 2(26) = 52

Then, according to triangle sum:

  • m∠K = 180 - (68 + 52) = 180 - 120 = 60

Then, find the missing angle:

  • m∠JKP = 60/2 = 30

Question 19

Sides are equidistant from incenter:

  • PN = PM = PO

Set up equation and solve or x:

  • 9x - 34 = 3x + 14
  • 9x - 3x = 14 + 34
  • 6x = 48
  • x = 8

Find one of equal segments:

  • PN = 3*8 + 14 = 24 + 14 = 38

Hence, MP = 38

Question 20

ΔMPJ and ΔOPJ are congruent right triangles as MP = OP and JP is common hypotenuse, therefore JM and JO are congruent as corresponding sides:

  • 2x + 3 = 5x - 45
  • 5x - 2x = 3 + 45
  • 3x = 48
  • x = 16

Then JM is:

  • JM = 2*16 + 3 = 32 + 3 = 35

We know MP = NP = 22.

Find JP using Pythagorean:

  • JP =
    JP = √(35^2+22^2)=√(1709) =41.34
User Jonas Malaco
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6.4k points