Question

Solve the system of equations. 2x + 4y = 12 3x + y = 3 (0, 3) (1, 0) (2, 2) (2, −3)

Answer 1

Solution is in the attachment!!

Answer 2

Answer:
`\Large\boxed{(0,\:3)}`

Explanation:

Given the system of equations

`1)2x+4y=12`

`2)3x+y=3`

Multiply 4 on both sides of the 2) equation

`3x* (4)+y*(4)=3*(4)`

`12x+4y=12`

Update the system of equations

`1)2x+4y=12`

`2)12x+4y=12`

Subtract the 1) equation from the 2) equation

`(12x+4y)-(2x+4y)=(12)-(12)`

Expand the parenthesis and simplify

`12x+4y-2x-4y=12-12`

`(12x-2x)+(4y-4y)=0`

`10x+0=0`

`10x=0`

Divide 10 on both sides

`10x/10=0/10`

`x={0}`

Substitute the x value into one of the equations

`3(0)+y=3`

`0+y=3`

`y=3`