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Solve the system of equations. 2x + 4y = 12 3x + y = 3 (0, 3) (1, 0) (2, 2) (2, −3)

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Solution is in the attachment!!

Solve the system of equations. 2x + 4y = 12 3x + y = 3 (0, 3) (1, 0) (2, 2) (2, −3)-example-1
User Sabrican Ozan
by
8.3k points
6 votes

Answer:
\Large\boxed{(0,\:3)}

Explanation:

Given the system of equations


1)2x+4y=12


2)3x+y=3

Multiply 4 on both sides of the 2) equation


3x* (4)+y*(4)=3*(4)


12x+4y=12

Update the system of equations


1)2x+4y=12


2)12x+4y=12

Subtract the 1) equation from the 2) equation


(12x+4y)-(2x+4y)=(12)-(12)

Expand the parenthesis and simplify


12x+4y-2x-4y=12-12


(12x-2x)+(4y-4y)=0


10x+0=0


10x=0

Divide 10 on both sides


10x/10=0/10


x={0}

Substitute the x value into one of the equations


3(0)+y=3


0+y=3


y=3

User JeremyK
by
9.4k points

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