Question

20 points!!
A EF = 22
B EF = 11
C EF = 16
D EF = 20

Answer 1

A

Explanation:

the midsegment EF of the trapezoid ABCD is half the sum of the parallel bases, that is

EF =
`(AB+DC)/(2)` ( substitute values )

x + 6 =
`(2x-9+x+5)/(2)`

x + 6 =
`(3x-4)/(2)` ( multiply both sides by 2 to clear the fraction )

2x + 12 = 3x - 4 ( subtract 3x from both sides )

- x + 12 = - 4 ( subtract 12 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

Then

EF = x + 6 = 16 + 6 = 22