Question

50) A cashier has a total of 121 bills, made up of fives and tens. The total value of the money is $895. How many ten-dollar bills does the cashier have?

Answer 1

Let's call the number of ten-dollar bills "x". Then the number of five-dollar bills would be 121-x.

The total value of the ten-dollar bills is 10x, and the total value of the five-dollar bills is 5(121-x).

So, we can set up an equation based on the total value of the money:

10x + 5(121-x) = 895

Expanding the right-side expression:

10x + 605 - 5x = 895

Combining like terms:

5x + 605 = 895

Subtracting 605 from both sides:

5x = 290

Dividing both sides by 5:

x = 58

So, the cashier has 58 ten-dollar bills.

Answer 2

89 Bills of 10$ and 1 of 5$

Explanation:

Pretty simple division which gets you 89.5 and that decimal is just the one 5$