Question

Triethylenemelamine has an empirical formula of CH N2 and a molar mass of

204.23 g/mole. What is the correct molecular formula?

Answer 1

=> calculate the molar mass of the empirical formula

1 * C * 12.01 + 1 * H * 1.01 + 2 * N * 14.01 = 41.03

204.23/41.03 = 5

the molecular formula is 5(CHN2)

which is
=> C5 H5 N10

Answer 2

The molecular formula for triethylenemelamine is C6H12N4.

Step-by-step explanation:

The empirical formula for triethylenemelamine is CH N2, which indicates that it contains one carbon (C), one hydrogen (H), and two nitrogen (N) atoms. The molar mass of triethylenemelamine is given as 204.23 g/mol. To determine the molecular formula, we need to find the ratio between the empirical formula's molar mass and the molar mass of the molecule.

The molar mass of the empirical formula is calculated by adding up the atomic masses of the atoms it contains: 12.01 g/mol for carbon, 1.007 g/mol for hydrogen, and 14.01 g/mol for nitrogen.

By dividing the molar mass of the molecule (204.23 g/mol) by the molar mass of the empirical formula (27.02 g/mol), we find that the molecule's molecular formula is C6H12N4.

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