Question

consider the following mixture problem and the table used to translate the problem Drink A is 20% fruit juice and drink B is 5% fruit juice. how much should be used in order to make 30 gal of a drink that is 10% fruit juice? complete the following table letting x=gallons of drink A and y=gallons of drink B.​

Answer 1

Substance Gallons % Fruit Juice

Drink A x 20%

Drink B y 5%

Total x + y = 30 10%

To find the number of gallons of Drink A and Drink B that should be used, we can write two equations based on the percentage of fruit juice.

20% * x = 10% * (x + y)

5% * y = 10% * (x + y)

Simplifying and solving for x and y:

x = 1.5 * y

10% * (x + y) = 10% * 30

y = 15

x = 1.5 * 15 = 22.5

So, we would use 22.5 gallons of Drink A and 15 gallons of Drink B to make a 30 gallon mixture that is 10% fruit juice.