Answer: Let's call the length of the rectangular court "L" and the width "W". Then, the perimeter of the court is 2 * (L + W) = 148 feet, so 2 * L + 2 * W = 148 feet.
And, according to the coach's estimate, the athlete ran a total of 4 * L + 7 * W = 353 feet.
We can use these two equations to find the dimensions of the court. Solving the first equation for W:
W = (148 - 2 * L) / 2.
Substituting this expression for W into the second equation:
4 * L + 7 * (148 - 2 * L) / 2 = 353
Expanding and simplifying the right side of the equation:
4 * L + 74 - 7 * L = 353
-3 * L = -279
L = 93 feet.
Finally, using the expression for W from the first equation:
W = (148 - 2 * L) / 2 = (148 - 2 * 93) / 2 = 32 feet.
So the dimensions of the sports court are 93 feet by 32 feet.
Explanation: