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Find an equation of the line passing through the points.
(-3,17) and (2. - 3)

User Reinderien
by
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1 Answer

5 votes

Answer: y = -4x + 29

Explanation:

To find the equation of the line passing through the points (-3, 17) and (2, -3), we can use the slope-point form of a line, which is given by:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, m is the slope of the line, and (x, y) are the coordinates of any other point on the line. To find the slope of the line, we can use the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in the coordinates of the two points, we have:

m = (-3 - 17) / (2 - (-3)) = -20 / 5 = -4

Next, we plug in the coordinates of one of the points and the slope into the slope-point form of a line:

y - 17 = -4(x - (-3))

Expanding the right side:

y - 17 = -4x + 12

Adding 17 to both sides:

y = -4x + 29

So the equation of the line passing through the points (-3, 17) and (2, -3) is: y = -4x + 29

User Eomeroff
by
8.1k points