Question

A 0.5 Kg ball is kicked and has a maximum kinetic energy of 225 J. What is the maximum height above the ground the ball will reach?

I am looking more for the formula because i have several to work.

Answer 1

45.9 m

Step-by-step explanation:

KE = 1/2mv² = 225 J

PE = mgh

If all the KE is converted to PE, then:

(0.50 kg)(9.8 m/s²)(h) = 225 J

h = (225 J) / (0.50 kg)(9.8 m/s²) = 45.9 m