Question

a rectangle has a perimeter of 158 cm and the given area of 804 cm^2 Its length is 7 more than five times its width. Write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

so i'm using the letter l for length w for width p for perimeter and a for area


l = 5w + 7
a = (5w+7) x w

p =2(5w+7) + 2w
= 10w + 14 +2w
p = 12w + 14
158cm = 12w + 14
12w = 144
w = (144/12) = 12

l = 5w + 7
so 5 x 12 + 7 = 67

width = 12cm length = 67cm

proven: area = 804cm^2 which is 12 x 67

hopes that u can understand my workings and that this helps :)