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Ahmed is a heating consultant. One of his clients has a boiler that is 62% efficient and uses heating oil that releases 4. 15 x 107 J kg-1 of heat energy when it bums in air. What mass of heating oil does the boiler need to heat 245 kg of water from 12. 0 °C to 68. 0 °C?

User Bkildow
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1 Answer

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Step-by-step explanation:

To calculate the amount of heating oil needed, we need to first determine the amount of energy required to heat the water. We can use the formula for calculating the energy required to heat a substance:

Q = mcΔT

where

Q is the energy required,

m is the mass of the substance,

c is the specific heat capacity of the substance, and

ΔT is the change in temperature.

For water, the specific heat capacity is 4.18 J/g°C.

Plugging in the values:

Q = 245 kg * 4.18 J/g°C * (68.0°C - 12.0°C) = 45,082,000 J

Next, we need to consider the efficiency of the boiler. The boiler is only 62% efficient, which means that only 62% of the energy released from the heating oil will actually be used to heat the water.

So the actual amount of energy required from the heating oil would be:

Q / 0.62 = 45,082,000 J / 0.62 = 72,619,355 J

Finally, we can use the heat energy released by 1 kg of heating oil to calculate the mass of heating oil required:

72,619,355 J / (4.15 x 107 J/kg) = 17.5 kg

So the boiler would need approximately 17.5 kg of heating oil to heat 245 kg of water from 12.0°C to 68.0°C.

User Pdp
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