Step-by-step explanation:
The ratio of the wavelength of sound in air to its wavelength in water can be calculated using the equation for the speed of sound in air and water. The speed of sound in air is dependent on temperature and pressure, and the speed of sound in water is dependent on temperature and the properties of the medium (e.g. salinity, pressure, etc.).
At 20.0°C, the speed of sound in air is approximately 340 m/s. The wavelength in air is given by the formula:
λ_air = v_air / f
where λ_air is the wavelength in air, v_air is the speed of sound in air, and f is the frequency of the sound.
The wavelength in water is given by the formula:
λ_water = v_water / f
where λ_water is the wavelength in water, v_water is the speed of sound in water (1540 m/s at 20.0°C), and f is the frequency of the sound.
The ratio of the wavelength of sound in air to its wavelength in water is given by:
λ_air / λ_water = v_air / v_water
Plugging in the known values for v_air and v_water, we find that:
λ_air / λ_water = 340 m/s / 1540 m/s = 0.22
So, the wavelength of sound in air is approximately 0.22 times the wavelength of the same sound in water.