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Given the sequence of numbers, a4=8, a5=12, a6=16, a7=20, and a8=24.

Which recursive rule can be used to find the nth term of the sequence, an?

a1=4; an=2an−1
a1=4; an=an−1+4
a1=−4; an=an−1+4
a1=−4; an=−2an−1

1 Answer

1 vote

Answer:


a_1=-4, \,a_n=a_(n-1)+4

Explanation:

Clearly, our common difference is
d=4, and we can see that the first term if we work backward from
a_4 is
a_1=-4.

Hence, by using the recursive formula
a_n=a_(n-1)+d, we have our final formula as
a_n=a_(n-1)+4

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