Question

Propane (C3H8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below.

C3H8 + 5O2 → 3CO2 + 4H2O

How many grams of oxygen are required to produce 37.15 g CO2?

37.15 g CO2 =
g O2

Answer 1

Answer: 45.02

thats what it is. Thats the answer. yep.

Answer 2

44.8 grams of O2

Step-by-step explanation:

The balanced equation tells us that 5 moles of O2 are required for every 1 3 moles of CO2 produced. This is a molar ratio of (5 moles O2)/(3 moles CO2).

Calculate the moles of CO2 in 37,15 grams of CO2:

The molar mass of CO2 is (12 + 2*16) = 44 grams/mole.

37.15 grams of CO2 is therefore ( 37.15 grams)/(44 grams/mole) = 0.84 mole of CO2.

Now use the molar ratio from above to calculate moles of O2 required:

(0.84 mole CO2)*[(5 moles O2)/(3 moles CO2)] = 1.4 moles O2

Convert 1.4 moles O2 to grams O2 by multiplying by the molar mass of O2: (1.4 moles O2)*(32 g/mole O2) = 44.8 grams of O2