Question

How do I solve for x ​

Answer 1

Answer:x=1

Explanation:

For this, you will need to use substitution.

we know that a²+b²=c²

plug it in

`x^2+3^2=y^2`

simplify to find

`x^2+9=y^2`

`y=√(x^2+9)`

repeat with the other side

`(x+8)^2+3^2=z^2`

`x^2+16x+73=z^2`

`z=√(x^2+16x+73)`

plug these in for the larger triangle

`y^2+z^2=(2x+8)^2`


`x^2+9+x^2+16x+73=4x^2+32x+64`

`2x^2+16x+82=4x^2+32x+64`

set equal to 0 and simplify

`-2x^2-16x+18=0`

pull out a -2

`x^2+8x-9=0`

factor

`(x-1)(x+9)=0`

x=-9,1

x cannot be negative since it a measurement so x=1