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A soccer player applies an average force of 180N during a kick. The kick accelerates a 45kg soccer

call from rest to a speed of 18 m/s. (a) What is the impulse exerted on the ball (b) What is the
collision time?​

1 Answer

7 votes

Answer:

The impulse exerted on the ball is 180 N and the collision time is 0.15 seconds.

Step-by-step explanation:

a) The impulse exerted on an object can be calculated by multiplying the force applied by the time over which it is applied:

Impulse = Force * time

We can use the equation of motion to find the time of collision:

v = u + at

where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration and t is the time of collision.

Combining these equations, we have:

Impulse = m * (v - u)

= m * a * t

= m * (v - 0) / t

= m * v / t

Plugging in the values, we have:

Impulse = 45 kg * 18 m/s / t

Dividing both sides of the equation by t, we have:

180 N = 45 kg * 18 m/s / t

Solving for t, we have:

t = (45 kg * 18 m/s) / 180 N

b) The collision time can be calculated by rearranging the above equation:

t = (45 kg * 18 m/s) / 180 N

t = 0.15 seconds

So the impulse exerted on the ball is 180 N and the collision time is 0.15 seconds.

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