Find the vertex of y=1/2x^2+2

Gongdo Gong asked Aug 15, 2023

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Gongdo Gong asked Aug 15, 2023

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20 votes

Answer:

(0,2)

Explanation:

Determine x-coordinate of vertex

$x=-(b)/(2a)\\ \\x=-(0)/((1)/(2))\\\\x=0$

Determine y-coordinate of vertex

y=(1)/(2)(0)^2+2

y=2

Therefore, the vertex is at
(0,2)

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