Question

A jet aircraft being launched from an aircraft carrier is accelerated from rest along a 94-meter track for 2.5s. What is the launch speed of the jet?

Answer 1

46.8 m/s.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

To solve for the launch speed of the jet, we need to use the equation of motion: v = at, where v is the final velocity, a is the acceleration and t is the time.

Given, a = 94m / (2.5s)^2 = 18.72 m/s^2

And t = 2.5s

So, v = at = 18.72 m/s^2 x 2.5s = 46.8 m/s.

Therefore, the launch speed of the jet is 46.8 m/s.