Question

Find the vertex of y=1/2x^2+2

Answer 1

`(0,2)`

Explanation:

Determine x-coordinate of vertex

`x=-(b)/(2a)\\ \\x=-(0)/((1)/(2))\\\\x=0`

Determine y-coordinate of vertex

`y=(1)/(2)(0)^2+2`

`y=2`

Therefore, the vertex is at
`(0,2)`