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Find the vertex of y=1/2x^2+2

1 Answer

10 votes

Answer:


(0,2)

Explanation:

Determine x-coordinate of vertex


x=-(b)/(2a)\\ \\x=-(0)/((1)/(2))\\\\x=0

Determine y-coordinate of vertex


y=(1)/(2)(0)^2+2


y=2

Therefore, the vertex is at
(0,2)

User Jorgy
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