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Solve. Show work.
log7 (3x + 1) = 2

1 Answer

5 votes

Answer:

X = 16

Explanation:

Hi again.

To solve this equation, use the logarithm property of equality to rewrite log7 (3x + 1) = 2 as 3x + 1 = 7^2.

We can then solve for x by subtracting 1 from both sides, giving us 3x = 7^2 - 1, then dividing both sides by 3 to get x = (7^2 - 1)/3.

Therefore, the solution is x = (7^2 - 1)/3.

So now, x will be 16.

Hope that can help :)

User Aplassard
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