Question

(3) I'm stuck pls help me with my algebra work show all ur steps
x=2y-7
3x-8y=-27

Answer 1

We can solve for y in the first equation and substitute it into the second equation to get a single equation in terms of x:

Solving for y in the first equation:
x = 2y - 7
2y = x + 7
y = (x + 7) / 2
Substituting this expression for y into the second equation:
3x - 8((x + 7) / 2) = -27
3x - 4x - 56 = -27
-x = 83
x = -83
Solving for y:
y = (x + 7) / 2
y = (-83 + 7) / 2
y = -38
So the solution to the system of equations is (x, y) = (-83, -38).

Answer 2

x = -1

y = 3

Explanation:

Equation 1: x=2y-7

Equation 2: 3x-8y=-27 ==> isolate x

Equation 3: 3x = 8y - 27 ==> isolate 3x by adding 8y on both sides

3 * (x = 2y - 7) ==> multiply 3 by equation 1 to get 3x

Equation 4: 3x = 6y - 21

3x = 8y - 27

- (3x = 6y - 21)

3x-3x = 8y-6y - 27-(-21) ==> subtract equation 4 from equation 3 to cancel x

0 = 2y - 27 + 21 ==> simplify

0 = 2y - 6 ==> solve for y

6 = 2y ==> add 6 on both sides to isolate y

y = 3 ==> divide 2 into both sides

Solve for x:

x=2(3) - 7 ==> plug in 3 for y in x=2y-7

x = 6 - 7

x = -1