Question

If 5.4 moles of Na₂CO₃ react with excess calcium hydroxide. how many grams of CaCO₃ will be produced?

Na₂CO₃+Ca(OH)₂=2NaOH+CaCO₃

Answer 1

540.47g approximately

Step-by-step explanation:

No. of moles in Na₂CO₃ = 5.4 moles

Mole ratio of Na₂CO₃ : CaCO₃ = 1:1

No. of moles in CaCO₃ = 5.4 moles

Mass of CaCO₃ = 5.4 × 100.0869

= 540.46926g