Question

A small fair charges different admission for adults and children; it charges $2.75 for adults, and $0.25 for children.

On a certain day, the total revenue is $6,962.50 and the fair admits 4900 people.
How many
adults and children were admitted?

Answer 1

Answer: Let's call the number of adults admitted "A" and the number of children admitted "C". We know that:

A + C = 4900 (total number of people admitted)

And the total revenue is:

2.75A + 0.25C = $6,962.50

We can use the first equation to solve for one of the variables in terms of the other:

C = 4900 - A

Substitute this expression for C into the second equation:

2.75A + 0.25(4900 - A) = $6,962.50

Expand and simplify the right side:

2.75A + 1225 - 0.25A = $6,962.50

2.5A = 5737.5

Solve for A:

A = 2298

So there were 2298 adults and 4900 - 2298 = 2602 children admitted.

Explanation: