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What is the equation of a line perpendicular to y=-2/5x-1 that passes through (2,-8)

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1 Answer

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Answer:

y = 5/2 x - 13

Explanation:

A line perpendicular to y=-2/5x-1 has a slope equal to the negative reciprocal of -2/5. The slope of the line passing through (2,-8) can be calculated as follows:

m = -(-5/2) = 5/2

The equation of the line in point-slope form is:

y - (-8) = (5/2)(x - 2)

Expanding the equation gives:

y + 8 = 5/2 x - 5

Solving for y:

y = 5/2 x - 5 - 8

y = 5/2 x - 13

The equation of the line is:

y = 5/2 x - 13

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