Question

A humane society has 73 dogs and cats to be adopted. The number of cats is 10 more than twice the number of dogs. How many of each animal is up for adoption?

Answer 1

52 cats

Explanation:

Let d be the number of dogs, then c = 2d + 10 is the number of cats.

The total number of animals is 73, so we have d + c = 73.

Substituting c = 2d + 10 into this equation, we get d + 2d + 10 = 73.

Combining like terms, we get 3d + 10 = 73.

Solving for d, we have 3d = 63, so d = 21.

Thus, there are 21 dogs and 2 * 21 + 10 = 52 cats up for adoption.