Answer:
The displacement can be represented as vectors in the x and y direction.
The displacement 3.62 m south can be represented as a vector of magnitude 3.62 m and direction -90°.
The displacement 8.10 m northeast can be represented as a vector of magnitude 8.10 m and direction 45°.
The displacement 14.6 m west can be represented as a vector of magnitude 14.6 m and direction -180°.
We can find the x and y components of each displacement vector, and then add those components to find the x and y components of the resultant displacement.
x component of the first displacement: 3.62 * cos(-90°) = 0 m
y component of the first displacement: 3.62 * sin(-90°) = -3.62 m
x component of the second displacement: 8.10 * cos(45°) = 5.65 m
y component of the second displacement: 8.10 * sin(45°) = 5.65 m
x component of the third displacement: 14.6 * cos(-180°) = -14.6 m
y component of the third displacement: 14.6 * sin(-180°) = 0 m
The x and y components of the resultant displacement are the sum of the x and y components of each individual displacement:
x component of the resultant displacement: 0 + 5.65 - 14.6 = -8.95 m
y component of the resultant displacement: -3.62 + 5.65 + 0 = 2.03 m
We can use the Pythagorean theorem to find the magnitude and direction of the resultant displacement:
resultant displacement = √(x^2 + y^2) = √(-8.95^2 + 2.03^2) = 9.06 m
direction = tan^-1(y/x) = tan^-1(2.03/-8.95) = 125.3°
So, the resultant displacement is 9.06 m at an angle of 125.3° with respect to the x-axis (east).
Step-by-step explanation: