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Two charges, Q1 = 10 nC and Q2 = -9.0 nC, are 15 cm apart. Find the strength of the electric field halfway between the two charges. Express your answer with the appropriate units. μΑ ?

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The strength of the electric field halfway between the two charges is determined as 30,400 N/C.

How to calculate the strength of the electric field?

The strength of the electric field halfway between the two charges is calculated as follows;

E = kq/r²

where;

  • k is Coulomb's constant
  • q is the magnitude of the charge
  • r is the distance between the charges

Halfway between the two charges = 15 cm / 2 = 7.5 cm

The strength of the electric field halfway between the two charges is calculated as;

E = k/r² (q₁ + q₂)

E = [(9 x 10⁹ ) / (0.075²) ] x (10 x 10⁻⁹ + 9 x 10⁻⁹ )

E = 30,400 N/C

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