Question

47. If the molar mass of X(HCO3)2 is 162 g mol-¹, determine the relative atomic mass of X. [H=1.0, C = 12.0. O = 16.0] A. B. C. D. 40 48 61 101 please answer with step by step solution​

Answer 1

X(HCO3)2 is X2(C2H2O6), so the total number of atoms for each element can be calculated:

2 X atoms

4 H atoms

6 C atoms

12 O atoms

Calculate the total atomic mass of the elements:

2 X atoms * atomic mass of X = 2X * atomic mass of X

4 H atoms * 1.0 amu = 4.0 amu

6 C atoms * 12.0 amu = 72.0 amu

12 O atoms * 16.0 amu = 192.0 amu

The molar mass of X(HCO3)2 is 162 g/mol, so the total atomic mass of the elements should add up to 162 g/mol:

2X * atomic mass of X + 4.0 amu + 72.0 amu + 192.0 amu = 162 g/mol

Solve for X by rearranging the equation:

2X * atomic mass of X = 162 g/mol - 4.0 amu - 72.0 amu - 192.0 amu = -12.0 amu

2X = -12.0 amu / atomic mass of X

Divide both sides by 2:

X = -6.0 amu / atomic mass of X

So the relative atomic mass of X is 6.0 amu.