Question

the x-component of the force on particle a when it is at x = 0.15 m is most nearly. (a) –20 n. (b) –2.0 n.(c) –1.0N(D) 2.0 N(E) 20 N

Answer 1

20 N (E)

Step-by-step explanation:

We are given potential energy from the graph, so to find the x-component, we can determine the work. We also know that the slope of potential energy is work, so we can do:

Δ∪= -W

Δ∪= -FΔx

F= - du/dx

To find du/dx, we find the slope at x = 0.15 m

du/dx = (-3 - - 0)/(0.25-0.1) = -20 N

Now replace

F= - du/dx

F= - - 20

F = 20 N

Note that it is positive 20 N

I hope this helped :)