Question

Two stones released at the same time with one thrown vertically upward from the ground with a velocity of 20m/s and the other dropped form a height collided with each other 2 seconds after their release. determine this height (g=9.8m/s^2​

Answer 1

The height at which the two stones collided is 78.4 meters, calculated using the formula h = u^2/2g, where u = 20 m/s and g = 9.8 m/s^2.

Step-by-step explanation: