Question

How many moles of gas occupy 157L at a pressure of 4.6 atm and a temperature of 471K?

Answer 1

Approximately 10 moles of gas.

Step-by-step explanation:

Ideal Gas Law = PV=nRT

n = (PV) / (RT)

n = (4.6 atm * 157 L) / (0.0821 Latm/mol-K * 471 K)

n = approximately 10 moles of gas.