Question

550 mL of gas at I atm is expanded to 960 mL. What will the pressure be?

Answer 1

Answer: If 550 ml of gas at 1 atm expands to 960 ml, the pressure will be 0.57 atm.

Step-by-step explanation:

It is an exercise of Boyle's Law that says: "At constant temperature the volume of a mass of a gas is inversely proportional to the pressure it exerts".

This means that if the volume is doubled the pressure is halved, and if the pressure is increased three times as much, the volume will be one third (1/3) of what it originally was.

The word inversely proportional means that if the pressure increases the volume decreases but proportionally.

550 mL of gas at I atm is expanded to 960 mL. What will the pressure be?

Data:

V₁ = 550 mL

P₁ = 1 atm

V₂ = 960 mL

P₂ = ?

The formula of this law is:

P₁V₁ = P₂V₂

Where

• P₁ = Initial pressure
• V₁ = Initial volume
• P₂ = Final pressure
• V₂ = Final volume

He asks us what the pressure would be after 960 mL, we solve the formula for the final pressure, then

`\boxed{\bold{P_1V_1=P_2V_2 \iff \ P_2=(P_1V_1)/(V_2) }}`

We substitute our data in the cleared formula and solve:

`\boxed{\bf{P_2=\frac{(1 \ atm \ * \ 550\\ot{mL}) }{960\\ot{mL}} }}`

`\boxed{\bf{P_2=0.57 \ atm }}`

If 550 ml of gas at 1 atm expands to 960 ml, the pressure will be 0.57 atm.