Question

How do I solve

What is the equation for a line that passes through the points (5,-2) and (-10,10)?

Answer 1

y=-4x+2

Explanation:

y2-y1/x2-x1

= 10-(-2)/-10-5

=12/-15 (divide by 3)

= -4/5x ---(Slope)

y=mx+b

-2=(-4/5)(5)+b

-2=-4+b (Add 4 on both Sides)

2=b

Put it all together

y=mx+b

Therefore,the equation is : y=-4/5x+2