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Write an exponential function y=abx whose graph passes through the points (1,2) and (3,50) .

1 Answer

3 votes

Answer:

y = 0.4·5^x

Explanation:

You want an exponential function y = a·b^x that passes through the points (1, 2) and (3, 50).

Setup

The given point values give two equations in two unknowns when used in the given exponential form:

y = a·b^x

2 = a·b^1

50 = a·b^3

Solution

Dividing the second equation by the first, we find b:

50/2 = (ab^3)/(ab)

25 = b^2 . . . . . simplify

5 = b . . . . . . . . . square root

Then the value of 'a' can be found from the first equation:

2 = a·5

a = 2/5 = 0.4

Exponential function

Using these values of 'a' and 'b', we have the exponential function ...

y = 0.4·5^x

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Additional comment

The exponential regression function of your calculator can tell you the same thing.

Write an exponential function y=abx whose graph passes through the points (1,2) and-example-1
User SmileyChris
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