Question

A stuntman jumped from a helicopter and opened his parachute. His height (in feet) at

time t seconds is given by the equation h (t) = -2t² 1000t+25000. What is his acceleration in ft/sec²?

Answer 1

Answer: The acceleration of the stuntman is given by the second derivative of the height function, which is:

h''(t) = d²h/dt² = (-2 * 2 * t * 1000 + 1000 * -2) = -4000t + 1000

So, the acceleration is -4000t + 1000 ft/sec².

Explanation: