Question

How much work is done in lifting a 60.0 kg crate a vertical distance of 10.0 m at a

constant velocity?

Answer 1

Formula for work:

`w=Fd`

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

Formula for force:

`F=ma`

force(measured in newtons) = mass(measured in kilograms) * acceleration(measured in m/s^2)

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Given:

`m=60kg`

`d=10m`

`a=9.8m/s^2`

`w=?`

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Finding force:

`F=ma`

`F=60*9.8`

`F=588N`

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Finding work:

`w=Fd`

`w=588*10`

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Answer:

`\fbox{w = 5880 Joules}`