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How long does it take a 2000-Kg car to stop from a velocity of 35 m/s if a braking force of 4000 Newtons is used?

User AKMalkadi
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Answer:

To find the time it takes for a car to stop from a velocity of 35 m/s using a braking force of 4000 N, we can use the following formula:

vf = vi + at

where

vf = final velocity (0 m/s in this case, since the car is stopping)

vi = initial velocity (35 m/s)

a = acceleration, which can be calculated as a = F/m, where F is the braking force (4000 N) and m is the mass of the car (2000 kg)

t = time

Rearranging the formula:

t = (vf - vi)/a = (0 - 35) / (4000 / 2000) = (35) / (2) = 17.5 s

Answer:

It takes the car 17.5 seconds to stop from a velocity of 35 m/s with a braking force of 4000 N.

User Bob Vork
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