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Expand (2x2^+3)(4x+5)-8x(x2^-2)

1 Answer

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Answer: Expanding the expression:

(2x * 2^+3) * (4x + 5) - 8x * (x^2^-2)

Start with the first set of parentheses:

2x * 2^+3 = 2x * 8 = 16x

Next, the second set of parentheses:

16x * (4x + 5) = 16x * 4x + 16x * 5 = 64x^2 + 80x

Finally, the third set:

-8x * (x^2^-2) = -8x * x^2^-2 = -8x * (1/x^2) = -8/x

So the final expanded form is:

64x^2 + 72x - 8/x

Explanation:

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