Question

A basket contain 3 red balls, 5 blue balls and 2 green balls. 2 ball are picked one after the other without replacement find the probability that: A. Both are red first is blue, the other is green Both are of different colour They are of the same color​

Answer 1

Explanation:

Total Number of balls = 3+5+2=10

a)Probability both are red: 3/10 * 2/9 = 1/15

b)First ball blue, other green : 5/10 * 2/9 = 1/9

c) Both are different color : (3/10*7/9)+(5/10*5/9)+(2/10*8/9)

=21/90+25/90+16/90=62/90=31/45

d)Both are same color: (3/10*2/9)+(5/10*4/9)+(2/10*1/9)

=6/90+20/90+2/90 = 28/90 = 14/45