Question

See Maths Questions attached

Answer 1

Basket A contains 8 balls, basket B contains 8 + 6 = 14 balls, and basket C contains 17 - (8 + 6) = 3 balls.

Let's call the number of balls in basket A "x".

Since there are 6 more balls in basket B than in basket A, we can write the equation for the number of balls in basket B as x + 6.

And since the total number of balls in baskets B and C is 17, we can write the equation for the number of balls in basket C as 17 - (x + 6) = 17 - x - 6.

So the total number of balls in baskets A, B and C is x + (x + 6) + (17 - x - 6) = x + x + 6 + 17 - x - 6 = 22.

Therefore, we can solve for x:

2x + 6 = 22

2x = 16

x = 8

So basket A contains 8 balls, basket B contains 8 + 6 = 14 balls, and basket C contains 17 - (8 + 6) = 3 balls.

Regarding the carpet, a room measuring 5 m x 7 m is 35 m². If each box of carpet covers 10 m², then 35 m² will need 35/10 = 3.5 boxes of carpet. This means that there will be 3.5 boxes * 10 m²/box = 35 m² of carpet. So there will be no carpet left over.

Answer 2

• 1) A = 5, B = 11, C = 6;
• 2) 5 m².

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Question 1

We have:

• A + B + C = 22
• B + C = 17
• B = A + 6

Use the difference of the first two equations to find A:

• A = 22 - 17 = 5

Then find B, using third equation:

• B = 5 + 6 = 11

Finally find C, using second equation:

• 11 + C = 17
• C = 17 - 11 = 6

Question 2

Area of the room is:

• 5*7 = 35 m²

If each box covers 10 m² we need to buy 4 boxes:

• 4*10 = 40 m²

Carpet left over:

• 40 - 35 = 5 m²